本文共 2202 字，大约阅读时间需要 7 分钟。
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11314 Accepted Submission(s): 4041
1 #include2 #include 3 #include 4 #include 5 #include 6 using namespace std; 7 #define mem(x,y) memset(x,y,sizeof(x)) 8 const int INF=0x3f3f3f3f; 9 const double PI=acos(-1.0);10 const int MAXN=50010;11 int ch[MAXN][30],word[MAXN],val[MAXN];12 char dt[50010][110];13 int sz;14 void initial(){15 sz=1;16 mem(ch[0],0);mem(word,0);mem(val,0);17 }18 void join(char *s){19 int len=strlen(s),k=0,j;20 for(int i=0;i
#include#include #include #include #include using namespace std;typedef long long LL;#define mem(x,y) memset(x,y,sizeof(x))#define SI(x) scanf("%d",&x)#define PI(x) printf("%d",x)#define P_ printf(" ")const int INF=0x3f3f3f3f;const int MAXN=1000010;//要开的足够大 int ch[MAXN][30];int word[MAXN];char str[50010][110];int val[MAXN]; int sz;int N;char l[110],r[110];void insert(char *s){ int k=0,j; for(int i=0;s[i];i++){ j=s[i]-'a'; if(!ch[k][j]){ mem(ch[sz],0); ch[k][j]=sz++; } k=ch[k][j]; word[k]++; } val[k]=1;}bool find(char *s){ int k=0,j; for(int i=0;s[i];i++){ j=s[i]-'a'; k=ch[k][j]; if(!word[k])return false; } if(val[k]!=1)return false; return true;}int main(){ int tp=0; sz=1; mem(ch[0],0);mem(val,0);mem(word,0); while(~scanf("%s",str[tp]))insert(str[tp++]);// printf("%d\n",tp); for(int i=0;i
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